differentiate with respect to x 1/(x^2-x+3)
farzeentahir55p2z6aj:
Clear the question please, I don’t understand whether it’s “x1” or x+1. It that were x1, it would have been typed as only x.
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= d/dx 1/(x^2 - x +3)
[(x^2-x+3)d/dx 1 - (1) d/dx (x^2-x+3)]/ (x^2-x+3)^2
= [ 0 - 2x + 1 -0 ] / (x^2-2x+3)^2
= ( -2x+1 ) / ( x^2 -2x+3)^2
[(x^2-x+3)d/dx 1 - (1) d/dx (x^2-x+3)]/ (x^2-x+3)^2
= [ 0 - 2x + 1 -0 ] / (x^2-2x+3)^2
= ( -2x+1 ) / ( x^2 -2x+3)^2
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