Question

differentiate with respect to x
$\sqrt{2x - 3}$
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Answer 1

LET y=$\sqrt{2x - 3}$

$\frac{dy}{dx} = \frac{d}{dx} \sqrt{2x - 3}$

$\frac{dy}{dx} = \frac{1}{2 \sqrt{2x - 3} } \frac{d}{dx} 2x - 3$

$\frac{dy}{dx} = \frac{1}{2 \sqrt{2x - 3} } \times 2 = \frac{2}{2 \sqrt{2x - 3} } = \frac{1}{ \sqrt{2x - 3} }$

Formula used in this sum is

$\frac{dy}{dx} = \frac{d}{dx} \sqrt{x} = \frac{1}{2 \sqrt{x} }$