Question

Find the area of an isoceles triangle whose base is 4cm and length of th equal side is 6cm

Answer 1

Answer:

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Answer 2

Answer:

Area = $8 \sqrt{2$ cm² = 11.312 cm²

Step-by-step explanation:

Given,

sides = 6 cm , 6 cm ,4 cm

∴ s = (6+6+4)/2  

s = 8

∴ Area = $\sqrt{{8} (8 - 6)(8 - 6)(8 - 4)}$

Area = $\sqrt{8 \times 2 \times 2 \times 4}$

∴  Area = $\sqrt{8 \times 16}$ = $\sqrt{8}$ × 4 = 2$\sqrt{2}$ × 4 = $8 \sqrt{2}$

Area = $8 \sqrt{2$ cm² = 11.312 cm²