differentiate x^2018
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The answer is given below :
Let, y = x^2018
Now differentiating with respect to x, we get
dy/dx = 2018 × x^2017
Rule :
d/dx (x^n) = n × x^(n - 1)
Thank you for your question.
Let, y = x^2018
Now differentiating with respect to x, we get
dy/dx = 2018 × x^2017
Rule :
d/dx (x^n) = n × x^(n - 1)
Thank you for your question.
Swarup1998:
that answer is also right...
wait... i am typing the right one
ok..thnx bro
now...
d/dx (sinx /1+sinx)
= {(1+sinx)d/dx (sinx) - sinx d/dx (1+sinx)}/(1+sinx)^2
= {(1 + sinx)(cosx) - sinx (cosx)}/(1+sinx)^2
= {(1 + sinx cosx - sinx cosx)}/(1+sinx)^2
= 1/(1+sinx)^2
hope this helps
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