Question

differentiate (x^2tanx)/(1+x) ​

Answer 1

$\bf\dfrac{dy}{dx}$

=$\bf\dfrac{x²tanx. d(1+x)/dx - (1+x). d(x²tanx)/dx}{ (1+x)² }$

=$\bf\dfrac{x²tanx - (1+x). x²d(tanx)/dx + tanx d(x²)/dx}{ x²+1+2x }$

=$\bf\dfrac{x²tanx - (1+x).(x²sec²x + 2xtanx)}{ x²+1+2x }$

=$\bf\dfrac{x²tanx - x²sec²x + 2xtanx +x³sec²x +2x²tanx}{ x²+1+2x }$

Answer 2

Answer:

karan ch*tiya hai ❣️❣️❣️