Differentiate : X^3 + 3X^2 + X
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Answer:
Given: y = x³ + 3x² + x
To find : Differentiation of "y" w.r.t "x"
i.e. dy/dx
Calculation :
y = x³ + 3x² + x
=> dy/dx = d(x³)/dx + 3 d(x²)/dx + d(x)/dx
=> dy/dx = 3x² + (3×2)x +1
=> dy/dx = 3x² + 6x + 1
Now, Another information about Differentiation :
1. It will be read as differential of "y" with respect to "x".
2. It represents the instantaneous change of "y" with change in "x".
3. Average change in "y" w.r.t to "x" is denoted as (∆y/∆x).
Answered by
111
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We can write this ,
Differenciate W.R.To X ,
We find here ,
...........(1)
We know ,
- if
So, Differentiate w.r. to x will be
Now, by (1)
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