Question

differentiate {x}^{95} + {x}^{23} + 2 {x}^{2} + 4x + 1​

Answer 1

EXPLANATION.

Differentiate = x⁹⁵ + x²³ + 2x² + 4x + 1.

As we know that,

⇒ d(x⁹⁵ + x²³ + 2x² + 4x + 1)/dx.

Using the formula,

d(xⁿ)/dx = nxⁿ⁻¹.

⇒ d(x⁹⁵ + x²³ + 2x² + 4x + 1)/dx.

⇒ 95x⁹⁵⁻¹ + 23x²³⁻¹ + 2(2)x²⁻¹ + 4.

⇒ 95x⁹⁴ + 23x²² + 4x + 4.

                                                                                                                     

MORE INFORMATION.

(1) = d(sin(x))/dx = cos(x).

(2) = d(cos(x))/dx = -sin(x).

(3) = d(tan(x))/dx = sec²x.

(4) = d(cot(x))/dx = -cosec²x.

(5) = d(sec(x))/dx = sec(x).tan(x).

(6) = d(cosec(x))/dx = -cosec(x).cot(x).

Answer 2

..QUESTION..

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★ Differentiate :

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ㅤㅤㅤㅤ➪ x⁹⁵ + x²³ + 2x² + 4x + 1

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..ANSWER..

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☯︎ Formula usable :

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ㅤㅤㅤ➪ $\bf{\dfrac{d(x^{n})}{dx}\:=\:nx^{n-1}}$

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•°• The equation becomes :

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$\leadsto \bf{\dfrac{d(x⁹⁵ + x²³ + 2x² + 4x + 1)}{dx}}$

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•°• $\mathfrak{according\:to\: the \:question}$

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$\implies \bf{\dfrac{d(x⁹⁵ + x²³ + 2x² + 4x + 1)}{dx}}$

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$\bf{\implies 95x^{95-1} + 23x^{23-1} + 2\times 2x^{2-1} + 4 }$

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$\implies \bf{95x⁹⁴ + 23x²² + 4x¹ + 4 }$

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$\leadsto \bf{\purple{95x⁹⁴ + 23x²² + 4x + 4 }}$ㅤㅤㅤ$\sf{\green{Ans....}}$

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ㅤㅤㅤ꧁ ʙʀᴀɪɴʟʏ×ᴋɪᴋɪ ꧂