Question

Differentiate
x^logx with
respect to x​

Answer 1

Step-by-step explanation:

y = x^logx

apply log on both sides,

=> log y = log x * x

=> 1/y dy/dx = log x *1 + x *1/x

=> 1/y dy/dx = log x + 1

=> dy/dx = y ( log x + 1 )

=> dy/dx = x^log x ( log x + 1 )