differentiate y=(1+4x^3)(1+2x^2)
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Answer:
y = (1+4x^3)(1+2x^2)
we know,
☑ if y = u.v
then, dy/dx= (u. dv/dx) + (v.du/dx)
☑ Differentiate wrt x
dy / dx = ( 1 + 4x^3 ) x ( 0 + 4x )
+ ( 1 + 2x^2 ) x ( 0 + 12x^2 )
= ( 1 + 4x^3 ) 4x + 12x^2 ( 1 + 2x^2 )
= 4x ((1 + 4x^3 ) + 3x ( 1 + 2x^2 ))
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