Question

Differentiate: y = 2x + 5% 3x-2​

Answer 1

Answer:

2x+5/3x-2

to find the first derivative differentiale using the quotient rule

f(x)=g(x)/h(x) then,

f(x)=h(x)g(x)-g(x)h(x)/(h(x))power2--------quotient rule

g(x)=2x+5=g(x=2)

h(x)=3x-2=h(x)=3

f(x)=(3x-2)2-(2x+5)3/(3x-2)power2

=6x-4-6x-15/(3x-2)power2

= -19/(3x-2) power 2

To obtain the 2nd derivative differentiate the derivative either use the quotient rule again or use the chain rule

given. f(x)=g(h(x)) then

= g(h(x)×h(x)------chain rule

= -19/(3x-2)= -19(3x-2)power-2

= -19×-2(3x-2) cube-3 .3

==114/(3x-2) cube 3

HOPE U LIKE THE ANSWER

pls Mark as brilliant....