Question

Differentiate
y=3x+3​

Answer 1

Answer:

✅Here's Your answer

$\sqrt{y} = \frac{(3x + 3) ^{3} }{x} \\ \\ \sqrt{y} = \frac{9 {x}^{3} + 9 + 81 {x}^{2} + 81x }{x} \\ \\ y = \sqrt{ \frac{9 {x}^{3} + 9 + 81 {x}^{2} + 81 }{x} } \\\ y = \frac{3x + 3 + 9x + 9}{x}$

$y=\frac{12x + 12}{x} \\ \\ y = \frac{12(x + 1)}{x}$

Hope it helps ✌