Question

differentiate y=cosx/sinx with. respect to x​

Answer 1

Explanation:

y=(cosx)

sinx

Taking log on both sides

logy=sinxlogcosx

Differentiating w.r.t. x, we get,

y

1

dx

dy

=cosxlogcosx−

cosx

sin

2

x

dx

dy

=(cosx)

sinx

[cosxlogcosx−

cosx

sin

2

x

]