Question

differentiate y=e^x^e^x with respect to x​

Answer 1

HIII......{¶}

THERE IS YOUR ANSWER.....{¶}

FIRST I MAKE SURE THAT YOU KNOW THE DIFFRENTIAL OF e^x WHICH IS ITSELF e^x........{∆}

WHEN TWO TERMS ARE WRITTEN IN PRODUCT THAN WE USE A SPECIAL TYPE OF RULE KNOWN AS PRODUCT RULE GIVEN BELOW.....{¶}

$let \: f(x) \: and \: g(x) \: are \: two \: \\ function \: written \: in \: product \ \\ with \: each \: other....... \\ \\ y = f(x)g(x) \\ \\ than \: \frac{dy}{dx} = f(x) \frac{dg(x)}{dx} + g(x) \frac{df(x)}{ax}$

NOW YOUR ANSWER IS WRITTEN BELOW......^_^

$y = {e}^{x} {e}^{x} \\ \\ \frac{dy}{dx} = \frac{d {e}^{x} }{dx} {e}^{x} + \frac{d {e}^{x} }{dx} {e}^{x} \\ \frac{dy}{dx} = {e}^{2x} + {e}^{2x} \\ \frac{dy}{dx} = 2 {e}^{2x}$

HOPE IT'S HELP U....