Question

differentiate y = e^x ( x+log x)​

Answer 1

Answer:

dy/dx= e^x(x+logx) + e^x[(x + 1)/x]

Step-by-step explanation:

Apply uv rule i.e derivative of uv= u'v + uv'

Also derivative of e^x is e^x only.

derivative of x is 1.

and derivative of logx is 1/x.