Math, asked by rajalaxmirajalaxmi08, 11 months ago

Differentiate y=xsinxcosx

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Answered by itzzmessndy
0

Answer:

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Answered by brainlyaryan12
4

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→Differentiate y=xsinxcosx

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y=Sin\theta .Cos\theta

\Large{\frac{dy}{dx}}

\frac{d(Sin\theta . Cos\theta)}{dx}

Cos\theta \times \frac{d(Sin\theta)}{dx}+ Sin\theta \times \frac{d(Cos\theta)}{dx}

Cos\theta \times Cos\theta + Sin\theta \times (-Sin\theta)

Cos^2\theta - Sin^2\theta

\huge{\pink{\overbrace{\underbrace{Cos^{\small{2}}\theta-Sin^{\small{2}}\theta}}}}

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Formulas Used :-

If\:y=u\times v

\frac{d(u\times v)}{dx}

\fbox{v\frac{du}{dx}+u\frac{dv}{dx}}

  • \fbox{\frac{d(Sin\theta)}{dx}=Cos\theta}
  • \fbox{\frac{d(Cos\theta)}{dx}=-Sin\theta}

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