Question

differentiation of 1/y​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\sf ANSWER}} \\ Differentiating \: with \: respect \: to \: y \\ \frac{d}{dy} ( \frac{1}{y} ) \\ \frac{d}{dy}( {y}^{ - 1} ) \\ - {(y)}^{ - 2} \\ - \frac{1}{ {y}^{2} }$

For differentiation,

$\frac{d}{dy}( {y}^{n} ) \\ it \: will \: be = > \\ (n \times {y}^{n - 1} )$

Answer 2

$\frac{d}{dy}\times{y} = -y^{- 2}$

Step-by-step explanation:

Lets$y = \frac{1}{y}$

taking differentiation w.r.t. 'y'

=$\frac{d}{dy}\times{y}$

= $\frac{d}{dy}\times\frac{1}{y}$

= $\frac{d}{dy}\times{y^{-1}}$

∵ $x^{n} = n\times{x^{n - 1}}$

then,

$= - 1\times{y^{ (- 1 - 1)}}$

$= -y^{- 2}$