Question

differentiation of (3t2- 2T)with respect to T is

Answer 1

$Function (f) = 3t^2 - 2t$

$Differentiation = \frac{\delta f}{\delta t}$

$\frac{\delta f}{\delta t} = \frac{\delta (3t^2 - 2t)}{\delta t}$

$\frac{\delta f}{\delta t} = 6t - 2$

Hence, the differentiation of $Function (f) = 3t^2 - 2t$ is:

$\frac{\delta f}{\delta t} = 6t - 2$