differentiation of cos^-1 {(4x^3/64)- 3/4 x}
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hey dear ...
here is your answer...
cos^-1 [(x^3/16)-3/4x]
dy/dx= -1/1+[x^3/16-3/4x]^2×1/16×3x^2-3/4
hope it will help you. ...
if u dont understand then ask me in the comment box.
here is your answer...
cos^-1 [(x^3/16)-3/4x]
dy/dx= -1/1+[x^3/16-3/4x]^2×1/16×3x^2-3/4
hope it will help you. ...
if u dont understand then ask me in the comment box.
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2
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no we didn't understand
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