Question

differentiation of Sin(ax+b)^2 w.r.t x​

Answer 1

Answer:

Differential of Sin(ax+b)^2 = 2a(ax+b).cos(ax+b)^2

Step-by-step explanation:

Let y = sin(ax + b)^2

Let (ax+b)^2 = u.

=> dy/du = cos(u) = cos(ax+b)^2 .......(1)

Let (ax+b)^2 = v.

=> du/dv = 2(u) = 2(ax+b) ....……….......(2)

Let (ax+b) = z.

=> dz/dx = a............................. ....... ......(3)

Multiply (1), (2) and (3),

dy/dx = 2a(ax+b).cos(ax+b)^2

Therefore, y' = cos(ax+b)^2.2(ax+b).

Answer 2

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Please refer to the attachment.