Differentiation of Sin (Sinx)....plz solve step by step
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Answered by
4
Hey!!!...Here is ur answer
d/dx [sin (sinx)]
=> cos (sinx) d/dx (sinx)
=> cosx cos (sinx)
Hope it will help you
d/dx [sin (sinx)]
=> cos (sinx) d/dx (sinx)
=> cosx cos (sinx)
Hope it will help you
Brainlyaccount:
nice answer
Answered by
1
Let us learn a few derivative formulas :
d/dx (sinx) = cosx
d/dx (cosx) = - sinx
Let, y = sin (sinx) ...(i)
Now, differentiating both sides with respect to x, we get
dy/dx = d/dx {sin (sinx)}
= cos (sinx) d/dx (sinx)
= {cos (sinx)} cosx,
which is the required derivative.
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