differentiation of sin2xcos²x
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d/dx(sin2xcos2x)
by product rule
(cos2x) .2cos2x) +sin2x. 2 (-sinx )x
2(cos2x)-2x(sin2x.sinx)
is a square
by product rule
(cos2x) .2cos2x) +sin2x. 2 (-sinx )x
2(cos2x)-2x(sin2x.sinx)
is a square
abhinav200180:
the answer given is -sin(root)x/2(root)x
okk
yes
fine
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