Physics, asked by Kunal770, 1 year ago

Differentiation of sin2xcos3x

Answers

Answered by vishalkhurana1

0

Answer:

sin2xcos3x

sin2x*d/dx(cos3x) + cos3x*d/dx(sin2x)

sin2x(-sin3x*3) + cos3x(cos2x*2)

2cos2xcos3x - 3sin2xsin3x

hope this helps

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Answered by shruti231298

0

Explanation:

=sin2x(-sin3x.3)+cos3x(cos2x.2)

=-3.sin2x.sin3x+2.cos2x.cos3x

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