Math, asked by navneet09, 1 year ago

differentiation of this equation

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Answered by abhi178
3
y = cosx³.sin²( x^5)

differentiate wrt x

dy/dx = cosx³.d( sin²(x^5)/dx + sin²(x^5)d(cosx³)/dx

= cosx³.{2sin(x^5).cos(x^5).5x⁴}+ sin²(x^5).{ -sinx³.3x²}

=5x⁴. cosx³.sin(2x^5) - 3x²sinx³.sin²(x^5)

[ note :- 2sin(x^5).cos(x^5) = sin(2x^5) ]
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