differentiation of x square sin x
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Let f(x)=(x2)(sinx), then f(x)=g(x)×h(x).
The derivative of this function is given by f'(x)=(g'(x)×h(x))+(h'(x)×g(x))
The derivative of g(x) or x2 is g'(x)=2×x2−1=2x
The derivative of h(x) or sinx is h'(x)=cosx.
Applying the product rule:
f'(x)=(g'(x)×h(x))+(h'(x)×g(x))
f'(x)=(2x(sinx))+(x2(cosx))
f'(x)=2xsinx+x2cosx
Hence, the derivative of y=(x2)(sinx) is y'=2xsinx+x2cosx.
Hopefully this helps!
The derivative of this function is given by f'(x)=(g'(x)×h(x))+(h'(x)×g(x))
The derivative of g(x) or x2 is g'(x)=2×x2−1=2x
The derivative of h(x) or sinx is h'(x)=cosx.
Applying the product rule:
f'(x)=(g'(x)×h(x))+(h'(x)×g(x))
f'(x)=(2x(sinx))+(x2(cosx))
f'(x)=2xsinx+x2cosx
Hence, the derivative of y=(x2)(sinx) is y'=2xsinx+x2cosx.
Hopefully this helps!
DINESH621:
welcome
can you solve this without using limit
i cant undrrstand
f g those are the function of limit
so I was saying can you solve that directly using the formulas
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