differentiation of (x²+3x)/x²
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Apply the rule of divide in differentiation
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Answer:
-3/x²
Explanation:
(x² + 3x)/x²
⇒ (x²/x²) + (3x/x²)
⇒ 1 + (3/x)
d/dx ( 1 + (3/x))
⇒ 0 + d/dx (3/x)
⇒ -3/x²
[ ∵ d/dx (1/x) = -1/x² ]
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