Question

Differentiation of y=2(3√x^2)
Here '3√' means cube root​

Answer 1

y = 2(3√x²)

It can be written as,

y = 2x^⅔

Now,

dy/dx = d2x^⅔/dx = 2 × ⅔ x⅔-¹

=>4/3 x^-⅓

=>$\frac{4}{3} x {}^{ \frac{ - 1}{3} }$

It can also be written as,

$\frac{4}{3 \sqrt[3]{x} }$

Cheers!