differentiation of y=logsinx
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The given date ,
Y = log(sinx)
Diff. with respect to x
dy/dx = 1/sinx ×d/dx[sinx]
dy/dx = 1/sinx ×cosx
dy/dx = cosx/sinx
dy/dx = cotx
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The given date ,
Y = log(sinx)
Diff. with respect to x
dy/dx = 1/sinx ×d/dx[sinx]
dy/dx = 1/sinx ×cosx
dy/dx = cosx/sinx
dy/dx = cotx
if you like my answer mark as brainliest
Answered by
1
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