Question

differentiation of y=logsinx

Answer 1

Hello , friends your answer is......


The given date ,

Y = log(sinx)

Diff. with respect to x


dy/dx = 1/sinx ×d/dx[sinx]

dy/dx = 1/sinx ×cosx

dy/dx = cosx/sinx

dy/dx = cotx


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Answer 2

$dy \div dx = cotx$