Question

Differentiation

Q. logx/x

Answer 1

$= \ \textgreater \ Given : \frac{logx}{x}$

$= \ \textgreater \ \frac{ \frac{d}{dx}(log(x))x - \frac{d}{dx}(x)log(x) }{x^2}$

$= \ \textgreater \ \frac{ \frac{1}{x} * x - 1 * log x }{x^2}$

$= \ \textgreater \ \frac{1 - logx}{x^2}$



Hope this helps!

Answer 2

Differentiation
Q. logx/x
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