Question

differentiation
$x2 + y2 + 2gx + 2fy + c = 0$
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Answer 1

Step-by-step explanation:

We have,

${x}^{2} + {y}^{2} + 2gx + 2fy = 0$

$\implies2x + 2y \frac{dy}{dx} + 2g + 2f \frac{dy}{dx} = 0$

$\implies2(y + f) \frac{dy}{dx} + 2(x + g) = 0$

$\implies \frac{dy}{dx} = - \frac{x + g}{y + f}$