Question

Differentuate 1/x^2 with respect to x

Answer 1

we know
$d {x}^{n} \div dx = n {x}^{n - 1}$
so
$d(x {}^{ - 2} ) \div dx = ( - 2) {x}^{ - 2 - 1} \\ = ( - 2) {x}^{ - 3}$
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Answer 2

differentiation of 1/x^n is nx^n-1 so by using this differentiation of 1/x^2 is-2/x^3