Math, asked by aadarshr13299, 8 months ago

differntiate 2 √cot (x^2) with respect to x .​

Answers

Answered by sweetylegend
0

Answer:

2  \sqrt{ \cot( {x}^{2}2 ) }  \\  x = 5

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Answered by Anonymous
0

Let y = 2 √cot(x^2)

Take y = 2√u where u= cot v where v = x^2

Then dy/dx = (dy/du)(du/dv)(dv/dx) by chain rule

=> dy/dx = 2(1/2√u)(-cosec^2 v)(2x)

= dy/dx = (1/√cot x^2)(-cosec^2 x^2)x^2

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