Question

differntiate y=e^x tanx.logx. with respect to x ​

Answer 1

Answer:

dy/dx=e^x  ( 1/x* tan x  logx *sec²x+ tanx*logx)

Step-by-step explanation:

y=e^x tanx.logx

dy/dx=e^x*d/dx( tax.logx) + tanx.logx*d/dx(e^x)

=e^x* (tanx d/dx( logx) +logx*d/dx( tanx) } + tan x.log x*e^x

=e^x* tanx *1/x +e^x*log x(sec²x) +e^x tan x* log x

dy/dx=e^x  ( 1/x* tan x  logx *sec²x+ tanx*logx)