Math, asked by koaham892, 11 months ago

differtiation of √x+1/x​

Answers

Answered by mnandhini335
0

Answer:

√x+1/x

x√x+1/x=0

x√x+1=0

x√x=-1

x=-1/√x

x=-√x/x

I hope that all

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Answered by Anonymous
5

Answer:

\large\boxed{\sf{ \frac{1}{2 \sqrt{x} } (1 -  \frac{1}{ x} )}}

Step-by-step explanation:

 \frac{d}{dx} ( \sqrt{x}  +  \frac{1}{ \sqrt{x} } ) \\  \\  =  \frac{d}{dx}  \sqrt{x}  +  \frac{d}{dx}  \frac{1}{ \sqrt{x} }  \\  \\  =  \frac{d}{dx}  {x}^{ \frac{1}{2} }  +  \frac{d}{dx}  {x}^{ -  \frac{1}{2} }  \\  \\  =  \frac{1}{2}  {x}^{ \frac{1}{2}  - 1}   -  \frac{1}{2}  {x}^{  - \frac{ 1}{2}  - 1}  \\  \\  =  \frac{1}{2}  {x}^{ -  \frac{1}{2} }   -  \frac{1}{2}  {x}^{ -  \frac{3}{2} }  \\  \\  =  \frac{1}{2 \sqrt{x} }  -  \frac{1}{2x \sqrt{x} }  \\  \\  =  \frac{1}{2 \sqrt{x} } (1 -  \frac{1}{ x} )

Concept Map :-

  •  \dfrac{d}{dx}  {x}^{n}  = n {x}^{n - 1}
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