Math, asked by gulzarmir00000, 20 days ago

diffrantiate y=4^3x

Answers

Answered by chandan454380
0

Answer:

if the question is

y =  {4}^{3x}

then the answer is

9x \times  {4}^{3x - 1}

Step-by-step explanation:

We need to apply chain rule over here

step 1 differentiate

 {4}^{3x}

then step 2 differentiate

3x

y =  {4}^{3x}  \\  \frac{dy}{dx}  =  \frac{d}{dx}  {4}^{3x}  \\  = 3x \times  {4}^{3x - 1}  \frac{d}{dx} 3x \\  = 3x \times  {4}^{3x - 1} \times 3 \\  = 9x \times  {4}^{3x - 1}

hope it helps please let me know in the comment section

Similar questions