Question

diffrentiate the value given below
${x}^{4} + {x}^{3} + 2{x}^{2} + x + 5$
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Answer 1

Answer:

$y. \: = 4 {x}^{3 } + 3 {x}^{2} + 4x + 1$

Explanation:

$y = {x}^{4} + {x}^{3} + 2{x}^{2} + x + 5 \\ \frac{dy}{dx} = 4 {x}^{3} + 3 {x}^{2} + 4x + 1$

Answer 2

Explanation:

$y = {x}^{4} + {x}^{3} + 2{x}^{2} + x + 5 \\ \frac{dy}{dx} = 4 {x}^{3} + 3 {x}^{2} + 4x + 1$