Question

Diffrentiate this one.

Answer 1

dY/dx = -sin(ax^2 + b) . d/dx (ax^2 + b)
= - Sin(...) . 2ax

Answer 2

Hope u like my process
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Differentiating the y W. R. T x
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$= > \frac{dy}{dx} = \frac{d( \cos(a {x}^{2} + b)) }{dx} \\ \\ or. \: \: \frac{dy}{dx} = - \sin(a {x}^{2} + b ) \times 2ax \\ \\ or. \: \: \frac{dy}{dx} = - 2ax \sin(a {x}^{2} + b)$
Hope this is ur required answer

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