Question

diffrentiation of x²logx + sinx√x​

Answer 1

Explanation:

$\frac{d}{dx} ( {x}^{2} log(x) + \sin(x) \sqrt{x}) = >$

${x}^{2} \frac{d}{dx}( log(x)) + log(x) \frac{d}{dx}( {x}^{2}) +$

$\sqrt{x} \frac{d}{dx}( \sin(x)) + \sin(x) \frac{d}{dx}( \sqrt{x}) = >$

$\frac{ {x}^{2} }{x} + 2x log(x) + \sqrt{x} \cos(x) + \frac{ \sin(x) }{2 \sqrt{x} }$

$= > x + 2x log(x) + \sqrt{x} \cos(x) +$

$\frac{ \sin(x) }{2 \sqrt{x}}$

Hope it helps you.