Question

Dilute one litre 1 molar h2so4 solution by 5 litre water the normality of that solution is

Answer 1

Answer: 0.33 N

Explanation:- Molarity : It is defined as the number of moles of solute present in one liter of solution.

$Molarity=\frac{\text {no of moles}}{\text {Volume of solution in L}}$

Normality is defined as  number of gram equivalents of solute present in one liter of solution.

$Normality=\frac{\text {no of gram equivalents}}{\text {Volume of solution in L}}$

${\text {Normality}}=\frac{\text {no of moles}\times n}{\text {Volume of solution in L}}$

n= basicity = number of $H^+$ ions in water= 2

Volume of solution = 6 L

${\text {Normality}}=\frac{1\times 2}{6L}=0.33N$

Answer 2

Answer:

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Explanation:

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Molarity=\frac{\text {no of moles}}{\text {Volume of solution in L}}Molarity=

Volume of solution in L

no of moles

Normality is defined as number of gram equivalents of solute present in one liter of solution.

Normality=\frac{\text {no of gram equivalents}}{\text {Volume of solution in L}}Normality=

Volume of solution in L

no of gram equivalents

{\text {Normality}}=\frac{\text {no of moles}\times n}{\text {Volume of solution in L}}Normality=

Volume of solution in L

no of moles×n

n= basicity = number of H^+H

+

ions in water= 2

Volume of solution = 6 L

{\text {Normality}}=\frac{1\times 2}{6L}=0.33NNormality=

6L

1×2

=0.33N