Question

Dilute sulfuric acid had a concentration of 4.90 g/dm3. What is its concentration in mol/dm3.

Answer 1

Answer:

The concentration of sulphuric acid in mol/$dm^{3}$  is 0.05 mol/$dm^{3}$.

Explanation:

Given concentration of sulphuric acid = 4.90 g/$dm^{3}$

Chemical formula of sulphuric acid = $H_{2} SO_{4}$

Molar mass of H = 1 g/mol

Molar mass of S = 32 g/mol

Molar mass of O = 16 g/mol

Molar mass of sulphuric acid,$H_{2} SO_{4}$  = (2 × 1) + (1 × 32) + (4 × 16) = 98 g/mol

Number of moles of $H_{2} SO_{4}$ = given mass ÷ molar mass

                                              = $\frac{4.90}{98}$ = 0.05 moles

Therefore the concentration of sulphuric acid in mol/$dm^{3}$  is 0.05 mol/$dm^{3}$.