Question

Dimension correctness of f=mv^2/gamma square

Answer 1

Answer:

Explanation:

Given

F=mV²/r

Dimensional Formula of Force= mx a       

                                                   =mxv/t

 L.H.S=F =M¹L¹T⁻²---------(1)

R.H.S=mv²/r       

 =M¹(L¹T⁻¹)²/L       

 =M¹L²T⁻²/L         

 =M¹L¹T⁻²------------(2)

By equation 1 and 2

L.H.S =R.H.S

Since the dimensions of F and mV²/r are equal... so equation is dimensionally correct.