Question

dimension of a wooden box is 14 cm into 18 cm into 17 cm and thickness is 1 cm what are its inner and outer surface area​

Answer 1

The total inner surface area and total outer surface area are 1224 sq.cm and 1592 sq.cm.

Step-by-step explanation:

Length of box = 14 cm

Breadth of box = 18 cm

Height of box = 17 cm

Total surface area of box = $2(lb+bh+hl)=2(14 \times 18 + 18 \times 17 + 17 \times 14)=1592 cm^2$

Thickness = 1 cm

Inner length = 14-(1+1)=12 cm

Inner breadth = 18-(1+1)=16 cm

Inner height = 17-(1+1)=15 cm

Total inner surface area $2(lb+bh+hl)=2(12 \times 16 + 16 \times 15 + 15 \times 12)=1224 cm^2$

Hence the total inner surface area and total outer surface area are 1224 sq.cm and 1592 sq.cm.

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Dimensions of a wooden box are 42 CM 30 cm and 27 CM if the thickness of the wooden box is 1 cm find its capacity

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Answer 2

Step-by-step explanation:

Length of box = 14 cm

Breadth of box = 18 cm

Height of box = 17 cm

Total surface area of box = 2(lb+bh+hl)=2(14 \times 18 + 18 \times 17 + 17 \times 14)=1592 cm^22(lb+bh+hl)=2(14×18+18×17+17×14)=1592cm

2

Thickness = 1 cm

Inner length = 14-(1+1)=12 cm

Inner breadth = 18-(1+1)=16 cm

Inner height = 17-(1+1)=15 cm

Total inner surface area 2(lb+bh+hl)=2(12 \times 16 + 16 \times 15 + 15 \times 12)=1224 cm^22(lb+bh+hl)=2(12×16+16×15+15×12)=1224cm

2

Hence the total inner surface area and total outer surface area are 1224 sq.cm and 1592 sq.cm.