dimension of acceleration
Answers
Answer:
Explanation:
The way to answer this and other dimension questions (known as “dimensional analysis”) is to simply choose a formula defining acceleration or any other variable in terms of the meter (length), kilo (mass), and/or time (second) or the MKS system, the cgs system, or other suitable system for your problem.
In the case of acceleration, first define the units of velocity V:
v = displacement / time = length / time. In the MKS system, v is meters / sec
Acceleration is the change of velocity per unit time:
change of velocity = delta(v) = v(final) - v(initial), which unit is still meters / sec
Acceleration = change of velocity per unit time = delta(v)/ time = (meters / sec) / sec.
That is, acceleration is the amount of meters/second that velocity changes each second.
Then a few somebodies follow with a discussion of instantaneous acceleration versus average acceleration, if at all. For the purpose of dimensional analysis, though, such discussion is irrelevant.
Since we physic enthusiasts tend to be lazy and like to write concisely, we do some algebraic manipulation, in a manner of speaking, and we say that
Acceleration = meters / (sec^2)
So there, you have it.
You can similarly define what a Newton really is as a unit by using a defining formulae:
F = m * a.
You can use the units of acceleration and the units of mass to find out the dimensions of a Newton in terms of the MKS system.
Dimension, in the sense used here, has nothing to do with geometrical dimensions; it is simply units of measurement.
Answer:
acceleration =velocity/time
Explanation:
L^1T^-2