Math, asked by anshitajain, 1 year ago

Dimension of room is 50cm×42cm×80cm then find the cost of paint a room if cost of paint is 3.5€/cm^2

Answers

Answered by Anonymous
2
Hello friend

Your answer is given below

Given that

Dimensions => 50 cm × 42cm × 80cm

So the length = 50 cm

Breadth = 42cm

Height = 80 cm

So area = 2 ( lb + bh + hl )

=>2 ( 50 x 42 + 42 x 80 + 80 x 50 )

=> 2 ( 2100 + 3360 + 4000 )

=> 2 x 9460

=> 18920 cm ^2

So the cost of 18920 cm^2 =>

=> 3.5 × 18920

=> Rs 66, 220
Answered by Panzer786
3
Heya !!!




Dimensions of room = (50 cm × 42 cm × 80 cm)



Length of room = 50 cm



Breadth of room = 42 cm




Height of room = 80. cm






Area is to be painted = TSA of room




=> 2 ( LB + BH + HL)





=> 2 ( 50 × 42 + 42 × 80 + 80 × 50 )





=> 2 ( 2100 + 3360 + 4000)







=> 2(9460)




=> 18920 cm²



Cost of painting of 1 cm² = Rs 3.5




Therefore,





Cost of painting of 18920 cm² = 3.5 × 18920 = Rs 66220.





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