Question

dimensional formula of normal reaction
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Answer 1

Or, C = [M1 L2 T-2] × [M1 L0 T0]-1 × [M0 L0 T0 K1]-1 = [M0 L2 T-2 K-1]. Therefore, specific heat capacity is dimensionally represented as [M0 L2 T-2 K-1].

Answer 2

Answer:

Explanation:

Dimensional Formula of Coefficient of Friction

The dimensional formula of coefficient of friction is given by,

[M0 L0 T0]

Where,

M = Mass

L = Length

T = Time

Derivation

Coefficient of friction (μ) = Frictional Force × [Normal Force]-1 . . . . (1)

Since, Force (F) = Mass × acceleration = Mass × velocity × [Time]-1

And, velocity = Displacement × [Time]-1

∴ The dimensions of Force = [M] × [LT-1] × [T]-1 = [M1 L1 T-2] . . . . (2)

On substituting equation (2) in equation (1) we get,

Coefficient of friction (μ) = Frictional Force × [Normal Force]-1

Or, μ = [M1 L1 T-2] × [M1 L1 T-2]-1 = [M0 L0 T0].

Therefore, the coefficient of friction is dimensionally represented as [M0 L0 T0].

normal reaction: The force exerted by a surface on an object in contact with it which prevents the object from passing through the surface; the force is perpendicular to the surface, and is the only force that the surface exerts on the object in the absence of frictional forces.

So if you have a one kilogram weight sitting on a table, the normal force acting on it is 9.8 Newtons, exactly counteracting the -9.8 Newtons acting on the weight from gravity. (Where positive force is Up).