Question

dinates of the point of division.
If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of a parallelogram taken in order, find x and y.


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Answer 1

Here is ur answer

A(1.2) , B(4,y) , C (x,6) ,D(3,5)

By mid - point formula (x1+x2/2,y1+y2/2)

Ac = (X+1/2, 6+2/2) = (x+1/2,8/2)= (x+1/2,4)

BD = (4+3/2,5+y/2)= (7/2,5+y/2)

We do Ac And Bd because opp. sides of parrallelogram are equal .

x+1/2=7/2 ; 2cancelled

x+1=7 then x=6

; 5+y/2=4 :::: 5+y=8

y=3

So x = 6,y=3

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