Question

dind value of k if the lines kx^2+4x-2y^2=0 are perpendicular to each other​

Answer 1

Answer:

equation acche se likho

Answer 2

Answer:

Answer

Given,

In equation , kx−5y+4=0

⇒5y=kx+4

y=(

5

k

)x+

5

k

So, the slope (m

1

)=

5

k

And, in equation 4x−2y+5=0

⇒2y=4x+5

y=2x+

2

5

So, the slope (m

2

)=2

As the line are perpendicular to each other

⇒m

1

×m

2

=−1

5

k

×2=−1

k=

2

(−1×5)

Hence, the value of k=

2

−