Question

Dinesh deposited Rs 8000 in a bank at the rate of 9 p.c.p.a. how much money will he get at the end of the year?​

Answer 1

Step-by-step explanation:

Principal - 8000

Rate of interest - 9 p.c.p.a.

Time - 1 year

Intrest - ?

Amount - ?

Intrest = Principal × Rate × Time

----------------------------------

100

Intrest = 8000 × 9 × 1

-------------------

100

Intrest = 80 × 9 × 1

Intrest = ₹ 720

Amount = Principal + Intrest

Amount = 8000 + 720

Amount = ₹ 8720

Dinesh get money ₹ 8720

Answer 2

${\huge{\red{\dag}}} \ {\large{\underline{\orange{\textsf{\textbf{Given :-}}}}}}$

• Principal = Rs. 8,000
• Rate % = 9% p.a.
• Time = 1 year

${\huge{\red{\dag}}} \ {\large{\underline{\green{\textsf{\textbf{To Find :-}}}}}}$

• Amount Dinesh will get after 1 year

${\huge{\red{\dag}}} \ {\large{\underline{\purple{\textsf{\textbf{Formula Used :-}}}}}}$

${\orange{\bigstar}} \ \ {\underline{\pink{\tt{A \ _{C.I.} = P \ \bigg ( 1 + \dfrac{R}{100} \bigg )^n}}}} \ \ {\orange{\bigstar}}$

where,

• A = Amount
• C.I. = Compound Interest
• P = Principal i.e. Rs. 8,000
• R = Rate % i.e. 9% p.a.
• n = Time period i.e. 1 year

${\huge{\red{\dag}}} \ {\large{\underline{\blue{\textsf{\textbf{Solution :-}}}}}}$

According to the question by using the formula of Amount, we get,

$\longmapsto {\sf{Amount = Rs. \ 8,000 \ \bigg ( 1 + \dfrac{9}{100} \bigg )^1}}$

Solving the above equation :

$: \implies {\sf{Amount = Rs. \ 8,000 \ \bigg ( 1 + \dfrac{9}{100} \bigg )^1}}$

$: \implies {\sf{Amount = Rs. \ 8,000 \ \bigg ( \dfrac{100 + 9}{100} \bigg )}}$

$: \implies {\sf{Amount = Rs. \ 8,000 \times \dfrac{109}{100}}}$

$: \implies {\sf{Amount = Rs. \ 8,0{\cancel{00}} \times \dfrac{109}{1{\cancel{00}}}}}$

$: \implies {\sf{Amount = Rs. \ 80 \times 109}}$

$: \implies {\sf{Amount = Rs. \ 8,720}}$

${\underline{\orange{\textsf{\textbf{Hence, Dinesh will get Rs. \ 8,720 at the end of the year.}}}}}$