Math, asked by kukku6594, 1 year ago

Dinesh speaks truth in 3/4 cases and abhishek lies in 1/5 cases. What is the percentage of cases in which both dinesh and abhishek contradict each other in stating a fact?

Answers

Answered by sancharimouri
2

Answer:

D and A will contradict each other when one speaks truth and other speaks lies.

Probability of D speak truth and A lies =

3 /4 × 1/5 = 3/20

Probability of A speak truth and D lies =

4 /5  ×  1/ 5  = 1 /5

The two probabilities are mutually exclusive.  

Hence, probabilities that D and A contradict each other:

=

3 /20 + 1/5  =  7/20  = 35%

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