Math, asked by kakranaryan5, 6 months ago

Dinesh went from place A to place B and from there to place C. A is 7.5 km km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. who travelled more and by how much?

Sol. Distance t egg travelled by Dinesh= AB+BC.
=7.5+12.7.
=20.2Km.

therefore' Dinesh travelled 20.2km.
Distance travelled by Ayub=AD+DC
=9.3+11.8.
=21.1km.
therefore' Ayub travelled 21.1km.
therefore' Ayub travelled more distance by=(21.1-20.2).
=0.9km.
therefore' Ayub travelled 0.9 km more than Dinesh.

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Answers

Answered by Adityaraj80511
3

Answer:

thank u .............

Answered by nafifaiz1717
1

Step-by-step explanation:

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