Math, asked by rudysingh266, 1 month ago

. Dinesh went from place A to place B and from there to place C. A is 5.5 km from B and B is 3 km from C. Ayub went from place A to place D and from there to place C. D is 4.03 km from A and C is 2.8 km from D. Who travelled more and by how much?

Answers

Answered by knandlal8789
1

Answer:

Distance travelled by Dinesh = AB + BC = 7.5+12=19.5

Distance travelled by Ayub = AD + DC = 9.3+11.8=21.1

Ayub travelled more than Dinesh .

difference=21.1-19.5=1.6

He travelled 1.6 km more than Dinesh

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